http://www.weistock.com/bbs/dispbbs.asp?BoardID=4&ID=4512&skin=0
找到个阿火版主写的策略,看看吧
试试可行不
s:cross("macd.def#min15"(26,12,9),"macd.def#min30"(26,12,9));
diff15:"macd.diff#min15"(26,12,9),linethick0;
dea15:"macd.dea#min15"(26,12,9),linethick0;
diff30:"macd.diff#min30"(26,12,9),linethick0;
dea30:"macd.dea#min30"(26,12,9),linethick0;
先调用30分钟周期以及15分钟周期的diff和dea值
然后进行判断:
if cross(diff15,dea15) and cross(diff30,dea30) then .......