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标题:这个AMA公式怎样翻译成金字塔可用

1楼
rooco_jiao 发表于:2010/10/28 22:04:58
 

Abbreviation: AMA

Category: Averages

 

Input Parameters:

 

Name

Range

Default

Time Series

 

Close

AMA Periods

Int >= 1

10

 

 

 

 

Calculation:

 

Y + (Smootiing Factor* (X - Y))

 

where

X = Time Series

Y = AMA one period ago (1st period Y is set to 1st period X)

Smoothing Factor = (Efficiency(Time Series, AMA Periods) * (2/(2+1) - 2/(30 + 1)) + 2/(30 + 1))^2

= (Efficiency(Time Series, AMA Periods) * (0.6667 ?0.0645) + 0.0645)^2 

= (Efficiency(Time Series, AMA Periods) * (0.6021667) + 0.0645)^2 

2楼
xian_0_9 发表于:2010/10/28 22:25:02
input:N(15,2,500); FASTC:=(1 / 3); SLOWC:=(2 / (30 + 1)); AMA:MD(C,N,FASTC,SLOWC),colorgreen,LINETHICK2;
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