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标题:k线开头的变量数据拿不到,是金字塔无法实现吗?

1楼
双保险 发表于:2012/8/4 6:21:05
程序说明

这个程序运行在一秒周期上 
ma5五分钟比上周期K线收盘低就显示enter。否则显示exit 

现在的问题:

 得不到5分钟K线的值。
ma5和ma10的数据是有的。
k线开头的变量数据都拿不到!

请高手指教!

[此贴子已经被作者于2012-8-4 6:23:15编辑过]
2楼
双保险 发表于:2012/8/4 6:21:42
Input: Period_Basic_Sec(1,1,60,1);

VARIABLE: ma5min = 0;
VARIABLE: k_c_5min = 0, k_c_5min_l = 0;
VARIABLE: b_5min = 0;
VARIABLE: ma5min_sample_cnt = 0;

ma5min_sample_cnt := 5 * 60 / Period_Basic_Sec;
ma5min := MA(CLOSE, ma5min_sample_cnt);

if time % 5 = 0 then
begin
b_5min := 1;
k_c_5min := CALLSTOCK('', VTCLOSE, 2, 0);
k_c_5min_l := CALLSTOCK('', VTCLOSE, 2, -1);
end
else
b_5min := 0;

if b_5min =1 then
begin
if ma5min < k_c_5min_l then
DRAWTEXT(1, C, "Enter");
if ma5min > k_c_5min AND 
  ma5min > k_c_5min_l then
   DRAWTEXT(1, C, "Exit");
end




3楼
双保险 发表于:2012/8/4 7:52:39
程序改写后无法打印出所需内容

Input: Period_Basic_Sec(1,1,60,1);

VARIABLE: ma5min = 0;
VARIABLE: k_c_5min_l = 0;
VARIABLE: b_5min = 0;
VARIABLE: ma5min_sample_cnt = 0;
VARIABLE: status = 0;

k_c_5min: "INDICATOR_K.CC#MIN5"; 

ma5min_sample_cnt := 5 * 60 / Period_Basic_Sec;
ma5min := MA(CLOSE, ma5min_sample_cnt);

if time % 5 = 0 then
begin
b_5min := 1;
k_c_5min := CALLSTOCK('', VTCLOSE, 2, 0);
k_c_5min_l := CALLSTOCK('', VTCLOSE, 2, -1);
end
else
b_5min := 0;

if time % 5 = 0 then
begin
if ma5min < k_c_5min AND
  status = 0 then
begin
   status := 1;
DRAWTEXT(1, C, "Enter");
    end
if ma5min > k_c_5min AND
  status = 1 then
begin
status := 0;
   DRAWTEXT(1, C, "Exit");
    end
end




改写后,依然无法drawtext
[此贴子已经被作者于2012-8-4 7:56:12编辑过]
4楼
王锋 发表于:2012/8/4 17:17:37

http://www.weistock.com/bbs/dispbbs.asp?boardid=4&Id=332 参考问题4,启用调试技巧看看程序的执行流程

共4 条记录, 每页显示 10 条, 页签: [1]


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