主题：求指导平仓问题

设计一个逢低加仓模型，价格下降一个档位就加仓   加仓后如果上涨一个档位就把加仓的部分平掉？？？请问问题出在哪里呢

H1：N+M;

L1：N-M;

A:=(H1-L1)/5;

A1：L1+A;

A2：L1+2*A;

A3：L1+3*A;

A4：L1+4*A;

MA1：MA(C,10);

手数：=1;

CON1：= REF(MA1,1)>REF(A4,1) AND MA1<A4;   

CON2：=REF(MA1,1)>REF(A3,1) AND MA1<A3;

CON3：=REF(MA1,1)>REF(A2,1) AND MA1<A2;

CON4：=REF(MA1,1)>REF(A1,1) AND MA1>A1;

CON5：=REF(MA1,1)<REF(A4,1) AND MA1>A4;

CON6: =REF(MA1,1)<REF(A3,1) AND MA1>A3;

CON7: =REF(MA1,1)<REF(A2,1) AND MA1>A2;

CON0: = H1-MA1<3 OR L-L1<3;

IF CON1 AND HOLDING = 0 THEN BEGIN    //下穿A4

     BUY (1，手数, MARKET);

     END

    IF CON2 AND HOLDING  =1 THEN BEGIN     //下穿A3JIA

        BUY (1，手数, MARKET);

        END

    IF CON3 AND HOLDING =2 THEN BEGIN      //A2JIA

     BUY (1，手数, MARKET);

     END

    IF CON4 AND HOLDING = 3 THEN BEGIN       //A1JIA

      BUY (1，手数, MARKET);

      END

  IF CON7 AND HOLDING = 4 THEN BEGIN            //A2 --

       SELL(1,手数,MARKET);

       END

  IF CON6 AND HOLDING = 3 THEN BEGIN                   //A3--

      SELL(1,手数,MARKET);

       END

  IF CON5 AND HOLDING = 2 THEN BEGIN                      //A4--

       SELL(1,手数,MARKET);

      END

 IF CON2 AND HOLDING = 0 THEN BEGIN      //下穿A3

      BUY (1，手数, MARKET);

      IF CON3 AND HOLDING = 1 THEN BEGIN         //下穿A2加仓

           BUY (1，手数, MARKET);

           END

       IF CON6 AND HOLDING = 2 THEN BEGIN

                SELL(1,手数,MARKET);

             END

        IF CON4 AND HOLDING = 2 THEN BEGIN          //下穿A1加仓

             BUY (1，手数, MARKET);

             END

        IF CON7 AND HOLDING = 3 THEN BEGIN

                   SELL(1,手数,MARKET);

              END          

  END           

IF CON3 AND HOLDING = O THEN BEGIN       //下穿A2

         BUY (1，手数, MARKET);

   IF CON4 AND HOLDING = 1 THEN BEGIN       //下穿A1 加仓

       BUY (1，手数, MARKET);

       END

       IF CON7 AND HOLDING =2 THEN BEGIN         //上穿A2减仓

             SELL(1,手数,MARKET);

             END

END

 IF CON4 AND HOLDING = 0 THEN BEGIN    //下穿A1

    BUY (1，手数, MARKET);

    END

CON1：REF(MA1,1)>REF(A4,1) AND MA1<A4;   

CON2：REF(MA1,1)>REF(A3,1) AND MA1<A3;

CON3：REF(MA1,1)>REF(A2,1) AND MA1<A2;

输出对饮条件，然后调试看下问题