主题：帮忙编写个程序:

两笔交易是指开仓2次，还是开仓1次平仓一次

也就是多空各开仓一次？如果不反向突破那么就是开多一次或者开空一次？

 

variable:n=0,m=0;
hh:valuewhen(time=133000,hhv(h,30));
ll:valuewhen(time=133000,llv(l,30));
tt:=time0<timetot0(closetime(0))-60;

if time>133000 and tt and h>hh and n=0 and holding<=0 then begin
 sellshort(1,0,marketr);
 buy(holding=0,1,marketr);
 n:=1;
end

if time>133000 and tt and l<ll and m=0 and holding>=0 then begin
 sell(1,0,marketr);
 buyshort(holding=0,1,marketr);
 m:=1;
end

if time0>=timetot0(closetime(0))-60 then begin
 sell(1,0,marketr);
 sellshort(1,0,marketr);
 n:=0;
 m:=0;
end

 

variable:n=0,m=0;
hh:valuewhen(time=140500,hhv(h,5));
ll:valuewhen(time=140500,llv(l,5));
tt:=time0<timetot0(closetime(0))-60;

if time>140500 and tt and h>hh and n=0 and holding<=0 then begin
 sellshort(1,0,marketr);
 buy(holding=0,1,marketr);
 n:=1;
end

if time>140500 and tt and l<ll and m=0 and holding>=0 then begin
 sell(1,0,marketr);
 buyshort(holding=0,1,marketr);
 m:=1;
end

if time0>=timetot0(closetime(0))-60 then begin
 sell(1,0,marketr);
 sellshort(1,0,marketr);
 n:=0;
 m:=0;
end

这种思路一样就改个时间参数的用户自行修改一下上面的代码

variable:n=0;

 

oo:=valuewhen(todaybar=1,o);

cc:=ref(close,todaybar);

 

hh:=max(oo,cc);

ll:=min(oo,cc);

 

if todaybar>5 and time0<timetot0(closetime(0))-60 and n=0 and h>hh and holding=0 then begin

    buy(holding=0,1,marketr);

    n:=1;

end

 

if todaybar>5 and time0<timetot0(closetime(0))-60 and n=0 and l<ll and holding=0 then begin

    buyshort(holding=0,1,marketr);

    n:=1;

end

 

if holding>0 and c<=enterprice*0.99 then sell(1,0,marketr);

if holding<0 and c>=enterprice*1.01 then sellshort(1,0,marketr);

 

if time0>=timetot0(closetime(0))-60 then begin

    sellshort(1,0,marketr);

    sell(1,0,marketr);

    n:=0;

end