主题：反手条件不同怎么改

if h>hi then buy(holding=0,1,market);

if h>hi then sellshort(1,0,market);

if H>hi+2 then begin

    sellshort(1,0,market);

    buy(holding=0,1,market);

end

 

开空的写法一样

那不就是我上面写的意思？你要反手就写一起，不要反手就拆开写

你代码里面一共4段都是反手语句，你按照我上面罗列出来的改改就行

 

if cc1>0 and l<lo then begin

 pc:=min(max(holding,0),cang1);

  if pc>0 then sell(1,pc,limitr,min(o,lo-0.2)-0.6);

 end

 

if cc1>0 and l<lo then begin

  kc:=cang1-pc;

 if pc>0 then sell(1,pc,limitr,min(o,lo-0.2)-0.6);

 if kc>0 then buyshort(1,kc,limitr,min(o,lo-0.2)-0.6);

 cc1:=0;

goto skip@;

end

 

 

if cc1>0 and l<lo-2 then begin

 pc:=min(max(holding,0),cang1);

 kc:=cang1-pc;

 if pc>0 then sell(1,pc,limitr,min(o,lo-0.2)-0.6);

 if kc>0 then buyshort(1,kc,limitr,min(o,lo-0.2)-0.6);

 cc1:=0;

goto skip@;

end

 

第一段的反手，就是这样改，你照着改下面的3段反手即可

if cc1>0 and l<lo then begin

  kc:=cang1-pc;

  if kc>0 then buyshort(1,kc,limitr,min(o,lo-0.2)-0.6);

 cc1:=0;

goto skip@;

end

 

if cc1>0 and l<lo then begin

 pc:=min(max(holding,0),cang1);

  if pc>0 then sell(1,pc,limitr,min(o,lo-0.2)-0.6);

 end

 

if cc1>0 and l<lo-2 then begin

 pc:=min(max(holding,0),cang1);

 kc:=cang1-pc;

 if pc>0 then sell(1,pc,limitr,min(o,lo-0.2)-0.6);

 if kc>0 then buyshort(1,kc,limitr,min(o,lo-0.2)-0.6);

 cc1:=0;

goto skip@;

end

哪个没有实现？